Given, (x+1x)10
We know that general term is tr+1=nCrXn−r.ar
Where n= 10 , X=x, a=1x
Hence,
tr+1=10Crx10−r.(1x)r
tr+1=10Crx10−r.1xr
=10Crx10−r−r
=10Crx10−2r
For independent term of x
x10−2r=x0
By compare of power of x we get
10-2r=0
r=5
Hence,
t5+1=10C5x10−2×r
t6=10C5x0
t6=10C5
6th term is independent of x , which is 10C6