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Question

Find the term independent of x in the expansion of
(3x2x2)15

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Solution

Let the term independent of x in the expansion of (3x2x2)15=10c5(3x)15k(2x2)k
=10c5 315k×(2)k×xnk2k.

For being the term independent of x
153k=0
3k=15
k=5
Hence, the term independent of x in the expansion of (3x2x2)15=10c5 (3x)10(2x2)5
=10c5 310×(2)5.

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