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Question

Find the term independent of x in the expansion of [12x1/3+x1/5]8

A
T3
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B
T5
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C
T6
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D
T8
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Solution

The correct option is C T6
We know that the expansion of (12x13+x15) will have term (x13)8b(x15)b
We want the power of x to be 0,
=>(8b)3b5=0=5(8b)3b
=>8b=40=>b=5 , so the term is T6

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