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Question

Find the term t15 of an A.P.:
4,9,14,.....

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Solution

The given A.P. is 4,9,14,....
We have,
a= First term =4
d= Common difference =5
We know that the nth term of an A.P. with first term a and common difference d is given by
tn=a+(n1)d
t15=a+(151)d
=4+(14)5
=4+70
t15=74

Hence, the term t15 is 74

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