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Byju's Answer
Standard XII
Mathematics
Nth Term of GP
Find the term...
Question
Find the terms
a
2
,
a
3
,
a
4
and
a
5
of a geometric sequence if
a
1
=
10
and the common ratio
r
=
−
1
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Solution
We know the terms in geometric series are in the form
a
r
,
a
r
2
,
a
r
3
,
a
r
4
,
a
r
5
,
.
.
.
.
Given,
a
1
=
10
,
r
=
−
1
a
2
=
a
1
r
=
10
(
−
1
)
=
−
10
a
3
=
a
1
r
2
=
10
(
−
1
)
2
=
10
a
4
=
a
1
r
3
=
10
(
−
1
)
3
=
−
10
a
5
=
a
1
r
4
=
10
(
−
1
)
4
=
10
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0
Similar questions
Q.
If
a
1
,
a
2
,
a
3
,
a
4
,
a
5
>
0
then
a
1
a
2
+
a
3
+
a
2
a
3
+
a
4
+
a
3
a
4
+
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+
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a
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a
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≥
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Q.
a
1
,
a
2
,
a
3
,
a
4
,
a
5
are first five terms of an A.P. such that
a
1
+
a
3
+
a
5
=
−
12
and
a
1
a
2
a
3
=
8
. Find the first term and the common difference.
Q.
If
a
1
,
a
2
,
a
3
,
.
.
.
.
.
.
.
a
n
are first n terms of an A.P. with first term
a
1
=
0
and common difference
d
≠
0
Then value of
a
3
−
a
2
a
2
+
a
4
−
a
2
a
3
+
a
5
−
a
2
a
4
.
.
.
.
.
.
.
.
.
.
.
.
a
n
−
a
2
a
n
−
1
is
Q.
a1,a2,a3,a4,a5 are the first five terms of an ap such that a1+a3+a5= -12 & a1a2a3=8 find the first term and common difference
Q.
Let the sequence
a
1
,
a
2
,
________
a
n
form an A.P. and let
a
1
=
0
, prove that
a
3
a
2
+
a
4
a
3
+
a
5
a
4
+
________
+
a
n
a
n
−
1
−
a
2
(
1
a
2
+
1
a
3
+
.
.
.
+
1
a
n
−
2
)
=
a
n
−
1
a
2
+
a
2
a
n
−
1
.
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Standard XII Mathematics
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