wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the third side of a triangle whose perimeter is 8m29m+4 and two of its sides are 3m25m and 4m2+12.

Open in App
Solution

Let the unknown side be x.

Perimeter of the triangle = sum of its three sides

8m29m+4 = (3m25m) + (4m2+12) +x

x = (8m29m+4)(3m25m)(4m2+12)

x = 8m29m+43m2+5m4m212

x = 8m24m23m29m+5m+412

x = m24m8


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Addition and Subtraction of Algebraic Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon