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Question

Find the third side of a triangle whose two sides are (3x25x) cm and (4x2+12) cm and perimeter is (8x29x+4) cm.

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Solution

Let the unknown side be y cm.

Perimeter of the triangle = sum of its three sides

( 0.5 marks )

8x29x+4 = (3x25x) + (4x2+12) +y

( 0.5 marks )

y=(8x29x+4)(3x25x)(4x2+12)

y=8x29x+43x2+5x4x212

( 0.5 marks )

y=8x24x23x29x+5x+412

y=(x24x8) cm

( 0.5 marks )

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