Question

Find the three consecutive numbers such that twice the first 3 times the second and 4 times the third together make 191

Answer 1

find 3 consecutive numbers such that twice the first , 3 times the second and 4 times the third together make 191 ?
Let n-1,n and n+1 be three consecutive numbers.
Given
2(n-1)+3n+4(n+1)=191
2n-2+3n+4n+4=191
9n+2=191
9n = 189
n = 21
So, n-1=20 and n+1=22
So the answer is 20,21,22