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Consecutive Numbers

Find the thre...

Question

Find the three consecutive odd numbers whose sum is 147.

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Solution

Dear student,

$C o n s i d e r t h e t h r e e c o n s e c u t i v e o d d n u m b e r b e (2 x + 1), (2 x + 3) a n d (2 x + 5) A c c o r d i n g t o t h e g i v e n c o n d i t i o n, 2 x + 1 + 2 x + 3 + 2 x + 5 = 147 \Rightarrow 6 x + 9 = 147 \Rightarrow 6 x = 138 \Rightarrow x = 23 S o, t h e o d d n u m b e r s a r e, 2 x + 1 = 2 \times 23 + 1 = 46 + 1 = 47 2 x + 3 = 2 \times 23 + 3 = 46 + 3 = 49 a n d 2 x + 5 = 2 \times 23 + 5 = 46 + 5 = 51 H e n c e, 47, 49 a n d 51 a r e t h e t h r e e c o n s e c u t i v e o d d n u m b e r w h o s e s u m i s e q u a l t o 147$

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