Question

Find the three different solutions for the following equation:

(i) $2x-y=7$

(ii)$y=6x$

(iii)$10x+11y=12$

Answer 1

$1)2x-y=7⟹y=2x-7$

$x=0⟹y=-7,x=1⟹y=-5,x=2⟹y=-3$

the three solutions are $(0,-7),(1,-5),(2,-3)$

$2)y=6x$

$x=0⟹y=0,x=1⟹y=6,x=2⟹y=12$

the three solutions are $(0,0),(1,6),(2,12)$

$1)10x+11y=12⟹y=\frac{1}{11}(12-10x)$

$x=0⟹y=\frac{12}{11},x=1⟹y=\frac{2}{11},x=2⟹y=-\frac{8}{11}$

the three solutions are $(0,-\frac{12}{11}),(1,\frac{2}{11}),(2,-\frac{8}{11})$