Question

find the three numbers whose ratio is 2:3:5 that sum upto to the squares of 608.

Answer 1

Dear student
$$\begin{gathered} Sincethenumbersareintheratioof2:3:5 \\ Sosupposethenumbersare2x,3x,5xrespectively. \\ Nowaccordingtothequestionwehave, \\ {\left(2x\right)}^2+{\left(3x\right)}^2+{\left(5x\right)}^2=608 \\ \Rightarrow 4x^2+9x^2+25x^2=608 \\ \Rightarrow 38x^2=608 \\ \Rightarrow x^2=16 \\ \Rightarrow x=\sqrt{16} \\ \Rightarrow x=4 \\ Therefore,thenumbersare2x=2\times 4=8,3x=3\times 4=12and5\times 4=20 \end{gathered}$$
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