Question

Find the time period of a simple pendulum when it is taken to a moon if it acts as a seconds pendulum on the earth. (take g_e = 6g_​m)

Answer 1

Dear student,

The time period of a simple pendulum on earth is given as

T = 2π(l/g)^1/2

now, for moon g' = g/6

this would mean that the gravitational force exerted by moon would be six times less compared to that of earth.

so, the time period would be

T' = 2π(l / g/6)^1/2

or

T' = √6T

T' > T

thus, time period of simple pendulum would increase on moon.

Regards