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Question

Find the time period of meeting of the minute hand and second hand of a clock. (Initial positions are shown in the figure below)


A
5960 min
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B
6059 min
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C
34 min
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D
38 min
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Solution

The correct option is B 6059 min

Angular velocity of minute hand, ωmin=2π60 rad min1
Angular velocity of second hand,
ωsec=2π1 rad min1
For second and minute hand to meet again
θsecθmin=2π
(ωsecωmin)T=2π
2π(1160)T=2π
T=6059 min

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