Find the time period of meeting of the minute hand and second hand of a clock. (Initial positions are shown in the figure below)
A
5960min
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B
6059min
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C
34min
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D
38min
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Solution
The correct option is B6059min
Angular velocity of minute hand, ωmin=2π60 rad min−1
Angular velocity of second hand, ωsec=2π1 rad min−1
For second and minute hand to meet again θsec−θmin=2π ⇒(ωsec−ωmin)T=2π ⇒2π(1−160)T=2π ⇒T=6059min