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Byju's Answer
Standard XII
Chemistry
Faraday's Second Law
Find the time...
Question
Find the time required to liberate 1 litre of
H
2
at STP in an electrolytic cell operating at 5 A.
A
19 min
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B
24 min
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C
29 min
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D
14.5 min
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Solution
The correct option is
B
29 min
22.4
L
corresponds to 1 mole or 2 g of hydrogen.
Hence, 1 L corresponds to
2
22.4
g
m
=
Z
I
t
Hence,
2
22.4
=
1
96500
×
5
×
t
or
t
=
1723
s
e
c
=
29
min.
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Similar questions
Q.
Find the time required to liberate of 1 litre of
H
2
at STP in an electrolytic cell operating at 2 A.
Q.
Find the time required to liberate 1.0 litre of hydrogen at STP in an electrolytic cell by a current of 5.0 A.
Q.
Calculate the time required to liberate
56
c
m
3
of hydrogen at
S
T
P
, if
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Q.
In the electrolysis of
H
2
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, 11.2 litre of
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2
liberated at cathode at STP. How much
O
2
will be liberated at anode under the same conditions?
Q.
An electric current is passed through two electrolytic cells connected in series, one containing
A
g
N
O
3
(aq) and other
H
2
S
O
4
(aq). The volume of
O
2
(in litres) measured at
25
o
C
and 750 mm Hg would be liberated in litre from
H
2
S
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, if 1 mole of
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are deposited from
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g
N
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.
(Round off to integer)
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