Find the torque about point O and A. →F = 5√3^i+5^j
A
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B
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C
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D
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Solution
The correct option is D
Torque about point O,→r=→r0×→F,→r0=^i+^j,→F=5√3^i+5^j →r=(^i+^j)×(5√3^i+5^j)=5(1−√3)^k Torque about point A,→r=→ra×→F,→ra=^j,^F=5√3^i+5^j →r=^j×(5√3^i+5^j)=5(−√3)^k