Find the total area of the shaded parts of the rectangle.

196

c m^{2}

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148

c m^{2}

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200

c m^{2}

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184

c m^{2}

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Solution

The correct option is D $184$ $c m^{2}$
We have, AF $=$ FE $=$ ED $=$ GD $=$ GF $=$ HG $=$ AH
Now, AF $+$ FE $= 16$ cm
$\Rightarrow$ AF $+$ AF $= 16$ cm $\Rightarrow$ AF $= 8$ cm
$∴$ Area of square AFGH $= 8 \times 8 = 64 c m^{2}$
Now, area of triangle HBCD $= (15 \times 16) C m^{2} = 240 c m^{2}$
Area of shaded part of rectangle $= 240 \div 2 = 120 c m^{2}$
$∴$ Total shaded area $= (64 + 120) c m^{2}$
$= 184 c m^{2}$ .

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Find the total area of the shaded parts of the rectangle.

The correct option is D 184 cm2We have, AF=FE=ED=GD=GF=HG=AHNow, AF+FE=16cm⇒AF+AF=16cm⇒ AF=8cm∴Area of square AFGH=8×8=64cm2Now, area of triangle HBCD=(15×16)Cm2=240cm2Area of shaded part of rectangle=240÷2=120cm2∴ Total shaded area=(64+120)cm2=184cm2.