Question

Find the total charge stored by the combination of capacitors shown in the figure below.

• A. $160\mu \text{C}$
• B. $320\mu \text{C}$
• C. $480\mu \text{C}$
• D. $640\mu \text{C}$

Answer 1

The correct option is B $320\mu \text{C}$


Upon observing the part $\left(\text{abdc}\right)$ of the circuit,

$\frac{2\mu F}{4\mu F}=\frac{4\mu F}{8\mu F}=\frac{1}{2}$

$V_p=V_q$$\Rightarrow 6\mu F$ is ineffective.

Similar is the case in the part $\left(\text{cdfe}\right)$ & $\left(\text{efhg}\right)$.

$V_q=V_r$ & $V_r=V_s$
The circuit is reduced to



$C_{eq}=8\mu \text{F}$

Using, $Q=CV$

$Q=(8\times 40)\mu C$

$Q=320\mu C$

Hence, option $\left(b\right)$ is the correct answer.