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Question

Find the total number of arrangements of the letters in the expression a3b2c4 when written at full length.

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Solution

There are 3a' s, 2b's and 4c' s.
So, the number of arrangements=9!4!3!2!
=9×8×7×6×5×44!×3×2×2
= 9×4×7×5 = 1260.
Hence, the total number of arrangements are 1260.


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