Find the total number of arrangements of the letters in the expression a3b2c4 when written at full length.
There are 3a' s, 2b's and 4c' s.
So, the number of arrangements=9!4!3!2!
=9×8×7×6×5×44!×3×2×2
= 9×4×7×5 = 1260.
Hence, the total number of arrangements are 1260.