Find the total number of electrons present in 96 g of SO 42- A- 5-781 - 1025 electronsB- 3-011 - 1025 electronsC- 50 electronsD- 98 electrons

The correct option is B 3.011× 10^25 electrons nbsp; nbsp; nbsp;Molar mass of nbsp;SO_4^2 =96 g/mol Electrons in an ion of SO_4^2 =16+(8× 4) + 2=50 mol ...

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Standard XII

Chemistry

Stoichiometric Calculations

Find the tota...

Question

Find the total number of electrons present in $96 g$ of $S O_{4}^{2 -}$ .

5.781 \times 10^{25}

electrons

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98

electrons

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50

electrons

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3.011 \times 10^{25}

electrons

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Solution

The correct option is D $3.011 \times 10^{25}$ electrons

Molar mass of $S O_{4}^{2 -} = 96 g/mol$
Electrons in an ion of $S O_{4}^{2 -} = 16 + (8 \times 4) + 2 = 50$
mol of $S O_{4}^{2 -}$ = $\frac{G i v e n m a s s}{M o l a r m a s s}$ = $\frac{96}{96}$ = 1 mol
Number of $S O_{4}^{2 -}$ ions = $6.023 \times 10^{23}$
Hence, $96 g$ of $S O_{4}^{2 -}$ ions contains $= 50 \times 6.023 \times 10^{23}$ electrons $= 3.011 \times 10^{25}$ electrons

Suggest Corrections

Find the total number of electrons present in 96 g of SO2−4.

The correct option is D 3.011×1025 electrons Molar mass of SO2−4=96 g/mol Electrons in an ion of SO2−4=16+(8×4)+2=50 mol of SO2−4 = Given massMolar mass = 9696 = 1 mol Number of SO2−4 ions = 6.023×1023 Hence, 96 g of SO2−4 ions contains =50×6.023×1023 electrons =3.011×1025 electrons

Find the total number of electrons present in $96 g$ of $S O_{4}^{2 -}$ .