Find the total number of moles of electrons in 6-023 - 1023 NO3- ions -

Total number of electrons in one NO_3^ ion = 7+(8 × 3) +1 = 32 So, the number of electrons in 6.023 × 10^23 NO_3^ ions are = 6.023 × 10^23× 32 = 32 moles ...

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Standard XII

Chemistry

Gay Lussac's Law, Avagadro's Law

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Question

Find the total number of moles of electrons in $6.023 \times 10^{23} N O_{3}^{-}$ ions ?

32

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Solution

The correct option is A $32$
Total number of electrons in one $N O_{3}^{-}$ ion $= 7 + (8 \times 3) + 1 = 32$

So, the number of electrons in $6.023 \times 10^{23} N O_{3}^{-}$ ions are
$= 6.023 \times 10^{23} \times 32$
$=$ 32 moles

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Find the total number of moles of electrons in 6.023×1023 NO−3 ions ?

The correct option is A 32Total number of electrons in one NO−3 ion =7+(8×3)+1=32 So, the number of electrons in 6.023×1023 NO−3 ions are =6.023×1023×32 = 32 moles

Find the total number of moles of electrons in $6.023 \times 10^{23} N O_{3}^{-}$ ions ?

The correct option is A $32$
Total number of electrons in one $N O_{3}^{-}$ ion $= 7 + (8 \times 3) + 1 = 32$

So, the number of electrons in $6.023 \times 10^{23} N O_{3}^{-}$ ions are
$= 6.023 \times 10^{23} \times 32$
$=$ 32 moles