Question

Find the total number of nucleons present in $12g$ of ${}^{12}C$ atoms.

Answer 1

In $12Kg$ of ${}^{12}C$ there are $6$ protons and $6$ neutrons and no. of nucleons are

$(6Protons+6neutrons)\times 6.022\times {10}^{23}$

$=12\times 6.022\times {10}^{23}Nucleons$

$=72.264\times {10}^{23}Nucleons$