Question

Find the total number of oxygen atoms in $3\times {10}^3$ formula units of $\left[Ni\right(H_{2}O{)}_6]C{l}_2$.

• A. $6\times {10}^3$
• B. $18\times {10}^3$
• C. $24\times {10}^3$
• D. $0.6\times {10}^3$

Answer 1

The correct option is B $18\times {10}^3$

Number of O-atoms in one formula unit of $\left[Ni\right(H_{2}O{)}_6]C{l}_2=6$
So, number of O-atoms in $3\times {10}^3$ formula units of $\left[Ni\right(H_{2}O{)}_6]C{l}_2=6\times 3\times {10}^3$
$=18\times {10}^3$