Question

Find the total resistance of the given circuit.

• A. 8 Ω
• B. 14 Ω
• C. 2 Ω
• D. 6 Ω

Answer 1

The correct option is A

8 Ω

The two resistors of $4\Omega$ are connected in parallel. Therefore the equivalent resistance $R_P$ of the two resistors will be $\frac{1}{R_p}=\frac{1}{4}+\frac{1}{4}$
$R_p=\frac{4\times 4}{4+4}$
$R_p=2\Omega$.
Now this combination of parallel resistance of value $R_p=2\Omega$ is in series with the $6\Omega$ resistor. Therefore the equivalent resistance of the combination $R_{eq}=R_p+R_s$ or,
equivalent resistance $R_{eq}=2\Omega +6\Omega =8\Omega$