Find the total surface area of a cone,if its slant height is 21 m and diameter of its base is 24 m.

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Solution

$Slant height of a cone (l)=21 m a n d d i a m e t e r o f i t s b a s e = 24 m ∴ R a d i u s (r) = \frac{24}{2} = 12 m N o w t o t a l s u r f a c e a r e a = π r (l + r) = \frac{22}{7} \times 12 (21 + 12) m^{2} = \frac{22}{7} \times 12 \times 33 m^{2} = \frac{8712}{7} m^{2} = 1244.57 m^{2}$

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