Find the total surface area of a cube whose volume is 64-m-3-4-m-296-m-264-m-224-m-2

The correct option is B 96 m^2Volume of cube= (side)^3 ⇒(side)^3 = 64 ⇒(side)^3 = (4)^3 ⇒ side = 4 m Total surface area of cube= 6(side)^2 =6 × 4^2 =96 m^2 ...

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Question

Find the total surface area of a cube whose volume is $64 m^{3} .$

4 m^{2}

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96 m^{2}

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64 m^{2}

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24 m^{2}

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Solution

The correct option is B $96 m^{2}$
$Volume of cube = (s i d e)^{3}$
$\Rightarrow (s i d e)^{3} = 64$
$\Rightarrow (s i d e)^{3} = (4)^{3}$
$\Rightarrow s i d e = 4 m$
$Total surface area of cube = 6 (s i d e)^{2}$
$= 6 \times 4^{2}$
$= 96 m^{2}$

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Find the total surface area of a cube whose volume is 64 m3.

The correct option is B 96 m2Volume of cube=(side)3 ⇒(side)3=64 ⇒(side)3=(4)3 ⇒side=4 m Total surface area of cube=6(side)2 =6×42 =96 m2

Find the total surface area of a cube whose volume is $64 m^{3} .$

The correct option is B $96 m^{2}$
$Volume of cube = (s i d e)^{3}$
$\Rightarrow (s i d e)^{3} = 64$
$\Rightarrow (s i d e)^{3} = (4)^{3}$
$\Rightarrow s i d e = 4 m$
$Total surface area of cube = 6 (s i d e)^{2}$
$= 6 \times 4^{2}$
$= 96 m^{2}$