Find the total surface area of a hollow cylinder open at both ends, if its length is $12 c m$ , external diameter is $8 c m$ and the thickness is $2 c m$ .

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Solution

Given for the hollow cylinder with open at both ends, length is $h = 12 c m$ , external diameter is $8 c m$ and the thickness is $2 c m .$

Then external radius is $r_{1} = 4$ cm and internal radius is $r_{2} = 4 - 2 = 2$ cm.

Now the total surface area of the hollow cylinder will be,

$= 2 \times π \times (r_{1} - r_{2}) \times h$

$= 2 \times π \times (4 - 2) \times 12$

$= 48 π$ cm $^{2}$ .

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Find the total surface area of a hollow cylinder open at both ends, if its length is 12 cm, external diameter is 8 cm and the thickness is 2 cm.

Find the total surface area of a hollow cylinder open at both ends, if its length is $12 c m$ , external diameter is $8 c m$ and the thickness is $2 c m$ .