Question

Find the total surface area of cubes having the following sides.

(i) $3cm$ (ii) $5cm$ (iii) $7.2m$ (iv) $6.8m$ (v) $5.5m$

Answer 1

(i) Length of each side of cube, $l=3cm$
Therefore, Total surface area of the cube, $=6\times l^2$
$=6\times 3^2$
$=6\times 9$
$=54c{m}^2$
(ii) Length of each side of cube, $l=5cm$
Therefore, total surface area of the cube $=6\times l^2$
$=6\times \left(5^2\right)$
$=6\times 25$
$=150c{m}^2$
(iii) Length of each side of cube, $l=7.2m$
Therefore, total surface area of the cube$=6\times l^2$
$=6\times (7.2{)}^2$
$=6\times 51.84$
$=311.04m^2$
(iv) Length of each side of cube, $l=6.8m$,
Therefore, total surface area of the cube$=6\times l^2$
$=6\times \left({6.8}^2\right)$
$=6\times 46.24$
$=277.44m^2$
(v) Length of each side of cube, $l=5.5m$
Therefore, total surface area of the cube $=6\times l^2$
$=6\times \left({5.5}^2\right)$
$=6\times 30.25$
$=181.50m^2$