Question

Find the total surface area of the square pyramid with base edge of length 10 m and slant height of 12 m.

Answer 1

Given,
Base edge length = 10 m and
Slant height = 12 m

Total surface area
$=(\text{Base edge}{)}^2+4\times (\frac{1}{2}\times \text{Base edge}\times \text{Slant Height})$

$={10}^2+4\times (\frac{1}{2}\times 10\times 12)$

$=100+4\times 60=340m^2$