Question

Find the trigonometric functions of ${225}^o$.

Answer 1

$\sin 225=\sin (45+180)=-\sin 45=-\frac{1}{\sqrt{2}}$

$\cos 225=\cos (45+180)=-\cos 45=-\frac{1}{\sqrt{2}}$

$\tan 225=\frac{\sin 225}{\cos 225}=1$

$\cot 225=\frac{1}{\tan 225}=1$

$\sec 225=\frac{1}{\cos 225}=-\sqrt{2}$

$\csc 225=\frac{1}{\sin 225}=-\sqrt{2}$