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Question

Find the trigonometric ratio equivalent to the following:

sin55+cos20+cot70+cosec85


A

cos35° + sin20° + tan20° + sec5°

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B

cos35° + sin70° + tan20° + sec5°

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C

cos35° + sin20° + tan70° + sec5°

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D

cos35° + sin20° + tan70° + sec85°

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Solution

The correct option is B

cos35° + sin70° + tan20° + sec5°


Since,

sinA=cos(90A)

cosA=sin(90A)

tanA=cot(90A)

cosecA=sec(90A)

secA=cosec(90A)

cotA=tan(90A)

Hence,sin55+cos20+cot70+cosec85=cos35+sin70+tan20+sec5


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