Find the two missing numbers in the arithmetic mean between $14$ and $50$ .

25

and

35

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26

and

38

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27

and

34

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21

and

32

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Solution

The correct option is C $26$ and $38$
14, ....... , ........ , 50
$n = 4, a = 14, a_{n} = 50$
First find the common difference:
$a_{n} = a_{1} + (n - 1) d$
$50 = 14 + (4 - 1) d$
$50 - 14 = 3 d$
$\frac{36}{3} = d$
$d = 12$
The missing numbers are 26 and 38.

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