wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the two natural numbers which differ by 5 and the sum of whose squares is 97.

Open in App
Solution

Let the two numbers be x and x + 5.
From the given information,
x2+(x+5)2=97
2×x2+10×x+2597=0
2×x2+10×x72=0
x2+5×x36=0
(x + 9) (x – 4) = 0
x = -9 or 4
Since, -9 is not a natural number. So, x = 4.
Thus, the numbers are 4 and 9.


flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon