Question

Find the valu of $x$ for which $(5x+2)$, $(4x-1)$ and $(x+2)$ are in A.P.

Answer 1

Given, $(5x+2),(4x-1),(x+2)$ are in A.P.

$\Rightarrow (4x-1)-(5x+2)=(x+2)-(4x-1)$

$4x-1-5x-2=x+2-4x+1$

$-x-3=-3x+3$

$2x=6$

$\therefore x=3$