Question

Find the value and express as a rational number in standard form:
(i) $\frac{2}{5}÷\frac{26}{15}$

(ii) $\frac{10}{3}÷\frac{-35}{12}$

(iii) $-6÷\left(\frac{-8}{17}\right)$

(iv) $\frac{-40}{99}÷(-20)$

(v) $\frac{-22}{27}÷\frac{-110}{18}$

(vi) $\frac{-36}{125}÷\frac{-3}{75}$

Answer 1

$$\begin{gathered} \left(\mathrm{i}\right)\frac{2}{5}÷\frac{26}{15}=\frac{2}{5}\times \frac{15}{26}=\frac{3}{13} \\ \left(\mathrm{ii}\right)\frac{10}{3}÷\frac{-35}{12}=\frac{10}{3}\times \frac{12}{-35}=\frac{-8}{7} \\ \left(\mathrm{iii}\right)-6÷\frac{-8}{17}=-6\times \frac{17}{-8}=\frac{51}{4} \\ \left(\mathrm{iv}\right)\frac{-40}{99}÷(-20)=\frac{-40}{99}\times \frac{1}{-20}=\frac{2}{99} \\ \left(\mathrm{v}\right)\frac{-22}{27}÷\frac{-110}{18}=\frac{-22}{27}\times \frac{18}{-110}=\frac{2}{15} \\ \left(\mathrm{vi}\right)\frac{-36}{125}÷\frac{-3}{75}=\frac{-36}{125}\times \frac{75}{-3}=\frac{36}{5} \end{gathered}$$