Question

Find the value ${27}^{\frac{1}{3}}\times {16}^{\frac{-1}{4}}$

Answer 1

${27}^{\frac{1}{3}}\times {16}^{\frac{-1}{4}}$
$\Rightarrow {\left(3^3\right)}^{\frac{1}{3}}\times {\left(2^4\right)}^{\frac{-1}{4}}$
$\Rightarrow \left(3^{3\cdot \frac{1}{3}}\right)\times \left(2^{4\cdot \frac{-1}{4}}\right)$
$\Rightarrow 3\times 2^{-1}$
$\Rightarrow \frac{3}{2}$