Find the value for x, y for:8y-3x+7=0, 2x-y+4=0

3 ,2

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-4, 7

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-5, -3

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-3, -2

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Solution

The correct option is D
-3, -2

8y-3x+7=0,

$\Rightarrow$ -3x+8y=-7

2x-y+4=0

$\Rightarrow$ 2x-y=-4

Solving equations (i) and (ii) we get we get

$\Rightarrow$ 13y=-26

$\Rightarrow$ $y = - \frac{26}{13} = - 2$

Substituting value of y in equation (ii), we get

2x-(-2)=-4

$\Rightarrow$ 2x+2=-4

$\Rightarrow$ 2x=-6

$\Rightarrow x = \frac{- 6}{2} = - 3$

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