Question

Find the value.

(i) 2¹⁰ (ii) 5³ (iii) ($-$7)⁴ (iv) ($-$6) ³ (v) 9³ (vi) 8¹ (vii) ${\left(\frac{4}{5}\right)}^3$ (viii) ${\left(-\frac{1}{2}\right)}^4$

Answer 1

$$\begin{gathered} \left(\mathrm{i}\right)2^{10}=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2 \\ =1024 \end{gathered}$$
$$\begin{gathered} \left(\mathrm{ii}\right)5^3=5\times 5\times 5 \\ =125 \end{gathered}$$
$$\begin{gathered} \left(\mathrm{iii}\right){\left(-7\right)}^4=\left(-7\right)\times \left(-7\right)\times \left(-7\right)\times \left(-7\right) \\ =2401 \end{gathered}$$
$$\begin{gathered} \left(\mathrm{iv}\right){\left(-6\right)}^3=\left(-6\right)\times \left(-6\right)\times \left(-6\right) \\ =-216 \end{gathered}$$
$$\begin{gathered} \left(\mathrm{v}\right)9^3=9\times 9\times 9 \\ =729 \end{gathered}$$
$$\begin{gathered} \left(\mathrm{vi}\right)8^1=8 \\ =8 \end{gathered}$$
$$\begin{gathered} \left(\mathrm{vii}\right){\left(\frac{4}{5}\right)}^3=\frac{4}{5}\times \frac{4}{5}\times \frac{4}{5} \\ =\frac{64}{125} \end{gathered}$$
$$\begin{gathered} \left(\mathrm{viii}\right){\left(-\frac{1}{2}\right)}^4=\left(-\frac{1}{2}\right)\times \left(-\frac{1}{2}\right)\times \left(-\frac{1}{2}\right)\times \left(-\frac{1}{2}\right) \\ =\frac{1}{16} \end{gathered}$$