Question

Find the value, in the simplest form, of $\frac{2^{n+4}-2\left(2^n\right)}{2\left(2^{n+3}\right)}$

• A. $\frac{1}{2}$
• B. $\frac{1}{4}$
• C. $\frac{3}{4}$
• D. $\frac{5}{8}$
• E. $\frac{7}{8}$

Answer 1

The correct option is E $\frac{7}{8}$

• $\frac{2^{n+4}-2\left(2^n\right)}{2\left(2^{n+3}\right)}=\frac{2^{n+4}-2^{n+1}}{2^{n+4}}=\frac{2^{n+1}}{2^{n+1}}\left(\frac{8-1}{8}\right)=\frac{7}{8}$