Find the value k. for which the point (-1, 3) lies on the graph of the equation 2x - y + k = 0.

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Solution

Given equation is $2 x - y + k = 0$
Given point $(- 1, 3)$
Accoding to question the point lies on line
$2 (- 1) - 3 + k = 0 - 2 - 3 + k = 0 k = 5$

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