1
Question
Find the value of −1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10] if a = 1, b = 0.
- -107
- -107
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Solution
The correct option is A -107
−1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10]
= −1[a−3{b−4(a−b+8)+4a}+10]
= −1[a−3{b−4a+4b−32+4a}+10]
= −1[a−3{5b−32}+10]
= −1[a−15b+96+10]
= −1[a−15b+106]
= −a+15b−106
If a=1,b=0,−a+15b−106=−1+0−106=−107
−1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10]
= −1[a−3{b−4(a−b+8)+4a}+10]
= −1[a−3{b−4a+4b−32+4a}+10]
= −1[a−3{5b−32}+10]
= −1[a−15b+96+10]
= −1[a−15b+106]
= −a+15b−106
If a=1,b=0,−a+15b−106=−1+0−106=−107
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