Find the value of
1/log_xy(xyz) + 1/log_yz(xyz) + 1/log_zx(xyz)

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Solution

The correct option is B
2
1/log_xy(xyz) + 1/log_yz(xyz) + 1/log_zx(xyz)
1/ log xyz/log xy + 1/ log xyz/log yz + 1/ log xyz/log xz
log xy/log xyz + log yz/log xyz + logxz/log xyz
log xy + log yz + log xz / log xyz
log ( xyyzxz) / log xyz
log xyz $^{2}$ /log xyz
2( log xyz / log xyz)
= 2

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Logarithm question

Simplify 1/ log_xy(xyz)+ 1/log_yz(xyz)+1/ log_zx(xyz)

\frac{{log}_{x y} x y}{{log}_{x y} x y z} + \frac{{log}_{y z} y z}{{log}_{y z} x y z} + \frac{{log}_{z x} z x}{{log}_{z x} x y z}

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