Find the value of ( $10^{- 1}$ × $4^{- 1}$ ) ÷ $2^{- 2}$ .

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Solution

( $10^{- 1}$ × $4^{- 1}$ ) ÷ $2^{- 2}$
$\frac{1}{10}$ × $\frac{1}{4}$ × 4
= $\frac{1}{10}$

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Similar questions

Q. Find the value of

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{(3^{- 1} + 4^{- 1} + 5^{- 1})}^{0}

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{({(\frac{- 2}{3})}^{- 2})}^{2}

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Find the value of (10−1 × 4−1) ÷ 2−2.

(10−1 × 4−1) ÷ 2−2 110 ×14 × 4 =110

Find the value of ( $10^{- 1}$ × $4^{- 1}$ ) ÷ $2^{- 2}$ .

( $10^{- 1}$ × $4^{- 1}$ ) ÷ $2^{- 2}$
$\frac{1}{10}$ × $\frac{1}{4}$ × 4
= $\frac{1}{10}$