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Question

Find the value of : 101×102

A
14562
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B
10302
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C
10402
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D
10202
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Solution

The correct option is B 10302
101×102
=(100+1)(100+2)
=(100)2+(1+2)(100)+(1)(2) ...[(x+a)(x+b)=x2+(a+b)x+ab]
=10000+300+2=10302

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