Find the value of 1010 - 990 using algebraic identities-

1010 can be written as nbsp; nbsp;(1000 + 10) and 990 can be written as (1000 10) 1010 × 990 = (1000+10)× (1000 10) nbsp; Using the identity (a nbsp; ...

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Standard VIII

Mathematics

Algebraic Identities

Find the valu...

Question

Find the value of $1010 \times 990$ using algebraic identities.

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Solution

1010 can be written as (1000 + 10) and 990 can be written as (1000 - 10)
$1010 \times 990 = (1000 + 10) \times (1000 - 10)$

Using the identity $(a + b) (a - b)$ = $a^{2}$ - $b^{2}$ ,
$(1000 + 10) (1000 - 10)$ = $1000^{2}$ - $10^{2}$
= $1000000 - 100$
= $999900$

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Find the value of 1010×990 using algebraic identities.

1010 can be written as (1000 + 10) and 990 can be written as (1000 - 10) 1010×990=(1000+10)×(1000−10) Using the identity (a+b)(a−b) = a2 - b2, (1000+10)(1000−10) = 10002-102 = 1000000−100 = 999900

Find the value of $1010 \times 990$ using algebraic identities.

1010 can be written as (1000 + 10) and 990 can be written as (1000 - 10)
$1010 \times 990 = (1000 + 10) \times (1000 - 10)$

Using the identity $(a + b) (a - b)$ = $a^{2}$ - $b^{2}$ ,
$(1000 + 10) (1000 - 10)$ = $1000^{2}$ - $10^{2}$
= $1000000 - 100$
= $999900$