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Question

Find the value of (105)2 by visualizing the identity (a+b)2=a2+2ab+b2.

A
10,025
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B
11,025
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C
12,025
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D
9,025
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Solution

The correct option is B 11,025
We have to find value of (105)2. So, let us visualize this with the help of diagram.


105 can also be written as (100+5).

So, the value of (105)2 will be area of square WXYZ.

Area of square WXYZ =(100+5)(100+5)=(100+5)2sq.units.

It can also be written as
Area of square WXYZ = Area of Yellow square + Area of Brown and Green rectangles + Area of White square

Brown and green rectangles have similar dimensions.

So, area of brown and green rectangles =(100×5) sq.units.

Area of white square is =(5×5) sq.units.

And, Area of yellow square =(100×100) sq.units

Now, (100+5)2=100×100+100×5+100×5+5×5)

(100+5)2=(100)2+2×100×5+52

(100+5)2=10,000+1,000+25=11,025.sq.units.

(105)2=11,025

Required value of (105)2 is 11,025.

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