find the value of −12−(−48)−[(−13)+(−8)−(−3)+4]
We have
−12−(−48)−[(−13)+(−8)−(−3)+4]
=−12+48−[−13−8+3+4] [∵−(−a)=a]
=36−[−21+12]
=36−[−9]
=36+9
=45
Find the maximum value and the minimum value of 3x4−8x3+12x2−48x+25 on the interval [0,3].
Find both the maximum value and the minimum value of
3x4 − 8x3 + 12x2 − 48x + 25 on the interval [0, 3]