1
Question
Find the value of −2(1−m2)−4(m2−(2−m2)) if m =0.
- 6
- 6
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Solution
The correct option is A 6
−2(1−m2)−4(m2−(2−m2))
=−2+2m2−4m2+8−4m2
=−2+2m2−8m2+8
=−2−6m2+8
=−6m2+6
If m=0,−6m2+6=0+6=6
−2(1−m2)−4(m2−(2−m2))
=−2+2m2−4m2+8−4m2
=−2+2m2−8m2+8
=−2−6m2+8
=−6m2+6
If m=0,−6m2+6=0+6=6
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