Find the value of $2^{10}$ × $3^{10}$ .

6^{10}

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2^{20}

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5^{10}

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3^{20}

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Solution

The correct option is A $6^{10}$
$2^{10}$ × $3^{10}$
= ${(2 \times 3)}^{10}$ [Since, $a^{m}$ × $b^{m}$ = ${(a b)}^{m}$ ]
= $6^{10}$

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Similar questions

Write each of the following as decimals:
(i) $65 + \frac{2}{10} + \frac{7}{100}$
(ii) $45 + \frac{9}{100}$
(iii) $88 + \frac{5}{10} + \frac{2}{1000}$
(iv) $\frac{3}{10} + \frac{7}{1000}$

Q. If

cosec θ = \sqrt{10} then \sec θ = ?

(a)

\frac{1}{\sqrt{1} 0}

(b)

\frac{2}{\sqrt{10}}

(c)

\frac{3}{\sqrt{10}}

(d)

\frac{\sqrt{10}}{3}

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3^{10}

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csc 10^{\circ} - \sqrt{3} sec 10^{\circ}

Q. The sum of the series

S = 1 + 2 (\frac{10}{11}) + 3 {(\frac{10}{11})}^{2} + \dots upto \infty

is equal to

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Find the value of 210 × 310.

The correct option is A 610210 × 310 = (2×3)10 [Since, am × bm = (ab)m] = 610

Find the value of $2^{10}$ × $3^{10}$ .

The correct option is A $6^{10}$
$2^{10}$ × $3^{10}$
= ${(2 \times 3)}^{10}$ [Since, $a^{m}$ × $b^{m}$ = ${(a b)}^{m}$ ]
= $6^{10}$