Question

Find the value of $2\left[\right(2^{-1}\times 4^{-1})÷2^{-2}]$.

Answer 1

Given, $2\left[\right(2^{-1}\times 4^{-1})÷2^{-2})$

= $2\left[\right(2^{-1}\times 4^{-1})÷2^{-2})$

= $2\left[\right(\frac{1}{2}\times \frac{1}{4})÷\frac{1}{4}]$

= $2\left[\right(\frac{1}{2}\times \frac{1}{4})÷\frac{1}{4}]$

= $2\left[\right(\frac{1}{8})÷\frac{1}{4}]$

= $2\left[\right(\frac{1}{8})\times \frac{4}{1}]$

= $2\left(\frac{1}{2}\right)$

= $1$